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Algorithm

Compare the Trrplets

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두개의 Integer Array를 입력받아 비교하여 같은 인덱스 위치의 값을 비교하여 count한 list를 return 하는 문제

 

- 내코드 

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;

public class Solution {

    // Complete the compareTriplets function below.
    static List<Integer> compareTriplets(List<Integer> a, List<Integer> b) {

    List<Integer> resultList = new ArrayList<>();
        resultList.add(0);
        resultList.add(0);

        for (int i = 0; i < a.size(); i++) {
            if (a.get(i) > b.get(i)) {
                resultList.set(0, resultList.get(0) + 1);
            } else if (b.get(i) > a.get(i)) {
                resultList.set(1, resultList.get(1) + 1);
            }
        }
        return resultList;
    }

    public static void main(String[] args) throws IOException {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

        List<Integer> a = Stream.of(bufferedReader.readLine().replaceAll("\\s+$", "").split(" "))
            .map(Integer::parseInt)
            .collect(toList());

        List<Integer> b = Stream.of(bufferedReader.readLine().replaceAll("\\s+$", "").split(" "))
            .map(Integer::parseInt)
            .collect(toList());

        List<Integer> result = compareTriplets(a, b);

        bufferedWriter.write(
            result.stream()
                .map(Object::toString)
                .collect(joining(" "))
            + "\n"
        );

        bufferedReader.close();
        bufferedWriter.close();
    }
}

resultList에 초기값 0을 셋팅하고 for문을 돌며 +1 해준다.

 

문제 출처 : www.hackerrank.com

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